C language: find all integers that can divide y and are odd numbers, and put them in the array indicated by B in the order from small to large

First , Let's study the criteria for odd numbers （ How to decide if it is an odd number ）：
Let's first analyze 10 An odd number within
1 3 5 7 9
We found that , they %2 all =1
So the criteria for odd numbers are %2!=0.

Next we just need to traverse + Just make a decision

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#define size 20
void fun(int y, int b[], int* m)
{
    
	int i = 0;
	int j = 0;
	while (i < size)
	{
    
		if (i % y == 0 && i % 2 != 0)
		{
    
			b[j] = i;			
			*m += 1;
			j++;
		}
		i++;
	}
}

int main()
{
    
	int y = 3,  m = 0;
	int b[size] = {
    0};
	fun(y, b, &m);
	printf("%d\n", m);
	int i = 0;
	while (b[i] != '\0')
	{
    
		printf("%d ", b[i]);
		i++;
	}
	return 0;
}