IP作业(2)RIP

一、实验要求

1、R1、R2、R3、R4、R5运行RIPV2，R6、R7运行RIPV1。

2、使用合理IP地址规划网络，各自创建环回接口。

3、R1创建环回172.16.1.1/24 172.16.2.1/24 172.16.3.1/24

4、要求R3使用R2访问R1环回。

5、减少路由条目数量，增加路由传递安全性。

6、R5创建一个环回模拟运营商，不能宣告。

7、R1 telnet R2环回实际 telnet 到R7上。

8、R6、R7路由器不能学习到达R1环回路由。

9、全网可达。

 

二、实验步骤

1、IP地址的分配及配置和环回接口的配置
AR1

[r1-GigabitEthernet0/0/0]ip a 192.168.1.1 30
[r1-GigabitEthernet0/0/1]ip a 192.168.1.9 30
[r1-LoopBack0]ip a 172.16.1.1 24
[r1-LoopBack1]ip a 172.16.2.1 24
[r1-LoopBack2]ip a 172.16.3.1 24
[r1-LoopBack3]ip a 1.1.1.1 24

AR2

[r2-GigabitEthernet0/0/0]ip a 192.168.1.2 30
[r2-GigabitEthernet0/0/1]ip a 192.168.1.5 30
[r2-LoopBack0]ip a 2.2.2.2 24

AR3

[r3-GigabitEthernet0/0/0]ip a 192.168.1.14 30
[r3-GigabitEthernet0/0/1]ip a 192.168.1.6 30
[r3-LoopBack0]ip a 3.3.3.3 24

AR4

[r4-GigabitEthernet0/0/0]ip a 192.168.1.13 30
[r4-GigabitEthernet0/0/1]ip a 192.168.1.10 30
[r4-GigabitEthernet0/0/2]ip a 192.168.1.21 30
[r4-GigabitEthernet4/0/0]ip a 192.168.1.17 30
[r4-LoopBack0]ip a 4.4.4.4 24

AR5

[isp-GigabitEthernet0/0/0]ip a 192.168.1.18 30
[isp-LoopBack0]ip a 5.5.5.5 24

AR6

[r6-GigabitEthernet0/0/0]ip a 192.168.1.22 30
[r6-GigabitEthernet0/0/1]ip a 192.168.1.25 30
[r6-LoopBack0]ip a 6.6.6.6 24

AR7

[r7-GigabitEthernet0/0/1]ip  a 192.168.1.26 30
[r7-LoopBack0]ip a 7.7.7.7 24
 

2、对各个路由器启动RIP协议
AR1

[r1]rip 1
[r1-rip-1]v 2
[r1-rip-1]network 192.168.1.0
[r1-rip-1]network 172.16.0.0
[r1-rip-1]network 1.0.0.0

AR2

[r2]rip 
[r2-rip-1]v 2   
[r2-rip-1]network 192.168.1.0
[r2-rip-1]network 2.0.0.0

AR3

[r3]rip
[r3-rip-1]v 2 
[r3-rip-1]network 192.168.1.0
[r3-rip-1]network 3.0.0.0

AR4

[r4]rip
[r4-rip-1]v 2
[r4-rip-1]network 192.168.1.0
[r4-rip-1]network 4.0.0.0

AR5

[isp]rip
[isp-rip-1]v 2
[isp-rip-1]network 192.168.1.0

AR6

[r6]rip
[r6-rip-1]v 1
[r6-rip-1]network 192.168.1.0 
[r6-rip-1]network 6.0.0.0

AR7

[r7]rip
[r7-rip-1]v 1 
[r7-rip-1]network 192.168.1.0 
[r7-rip-1]network 7.0.0.0

3、对AR5配置缺省和AR6的互通
AR5

[isp-rip-1]default-route originate 

AR6

[r6-GigabitEthernet0/0/0]rip version  2

4、对AR1上的环回做手工汇总和空接口配置
AR1

[r1]int g0/0/0
[r1-GigabitEthernet0/0/0]rip summary-address 172.16.0.0 255.255.252.0
[r1-GigabitEthernet0/0/1]rip summary-address 172.16.0.0 255.255.252.0 
[r1]ip route-static 172.16.0.0 22 NULL 0

5、R3上抓取流量并修改开销值
AR3

[r3]acl 2000  
[r3-acl-basic-2000]rule permit source 172.16.0.0 0  
[r3-acl-basic-2000]rule permit source 1.1.1.0 0
[r3]int g0/0/0
[r3-GigabitEthernet0/0/0]rip metricin 2000 10

5、R1和R2做手工认证
AR1

[r1]int g0/0/0
[r1-GigabitEthernet0/0/0]rip authentication-mode simple cipher 123456

AR2

[r2]int g0/0/0  
[r2-GigabitEthernet0/0/0]rip authentication-mode simple cipher 123456

6、R6、R7路由器不能学习到达R1环回路由配置
[r6]acl 2000
[r6-acl-basic-2000]rule deny source 172.16.0.0 0
[r6-acl-basic-2000]rule deny source 1.1.1.0 0
[r6-acl-basic-2000]rule permit source any 
[r6-rip-1]filter-policy 2000 import 

7、R7上开启 telnet 服务及R2上nat 映射服务
AR7

[r7]aaa
[r7-aaa]local-user xujialong privilege level 15 password cipher 123456
[r7-aaa]local-user xujialong service-type telnet    
[r7]user-interface vty 0 4
[r7-ui-vty0-4]authentication-mode aaa

AR2

[r2]int g0/0/0
[r2-GigabitEthernet0/0/0]nat server protocol tcp global interface loopback 0 23 
inside 7.7.7.7 23
Are you sure to continue?[Y/N]:y

8、对R2和R4上将数据包的传输方向进行策略改变
AR2

[r2]acl 2000 
[r2-acl-basic-2000]rule permit source 7.0.0.0 0
[r2]int g 0/0/0
[r2-GigabitEthernet0/0/0]rip metricin 2000 10

AR4
[r4]acl 2000
[r4-acl-basic-2000]rule permit source 192.168.1.0 0
[r4]int g 0/0/1
[r4-GigabitEthernet0/0/1]rip metricin 2000 10