The problem of monkeys eating peaches in classic exercises of C language

The problem of monkeys eating peaches ：
The monkey picked some peaches on the first day , Half eaten immediately , It's not addictive , Another one , The next morning I ate half of the rest of the peaches , Another one . After that, I ate half and one of the rest of the day before every morning . To the first 10 When I want to eat again in the morning , See there's only one peach left . Ask how much you picked on the first day .
C The program code is as follows ：

/* The problem of monkeys eating peaches ： The monkey picked some peaches on the first day , Half eaten immediately , It's not addictive , Another one , The next morning I ate half of the rest of the peaches , Another one .  After that, I ate half and one of the rest of the day before every morning . To the first 10 When I want to eat again in the morning , See there's only one peach left . Ask how much you picked on the first day . */
#include <stdio.h>
int main(int argc, char const *argv[])
{
    
    int n = 1;
    for (int i = 9; i > 0; i--)
    {
    
        n = (n + 1) * 2;
    }
    printf("%d ", n);
    return 0;
}
/* List all mathematical methods ： （1+1）×2=4（ individual ） （4+1）×2=10（ individual ） （10+1）×2=22（ individual ） （22+1）×2=46（ individual ） （46+1）×2=94（ individual ） （94+1）×2=190（ individual ） （190+1）×2=382（ individual ） （382+1）×2=766（ individual ） （766+1）×2=1534（ individual ）  answer ： On the first day, I picked 1534 A peach .*/

The operation result is as shown in the figure ：