True MySQL interview question (21) - Finance - overdue loan

The loan is overdue

A financial loan company , You need to know about the overdue loans of users . There is a user in the company's database " Loan overdue days " surface .

When overdue days =0 when , Write it down as M0,

Overdue days in [1,30] In the interval , Write it down as M1,

Overdue days in [31,60] In the interval , Write it down as M2,

Overdue days in [61,90] In the interval , Write it down as M3,

Other higher overdue days are recorded as M4+,

Now we need to analyze each overdue period in the database （M0、M1、M2、M3、M4+） Number of orders , If it's you , How will it be analyzed ？

give the result as follows ：

SELECT 
SUM(CASE WHEN  Days overdue =0 THEN 1 ELSE 0 END) AS M0,
SUM(CASE WHEN  Days overdue  BETWEEN 1 AND 30 THEN 1 ELSE 0 END) AS M1,
SUM(CASE WHEN  Days overdue  BETWEEN 31 AND 60 THEN 1 ELSE 0 END) AS M2,
SUM(CASE WHEN  Days overdue  BETWEEN 61 AND 90 THEN 1 ELSE 0 END) AS M3,
SUM(CASE WHEN  Days overdue >90 THEN 1 ELSE 0 END) AS M4
FROM  Loan overdue days