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原神方石机关解密

2022-06-24 06:39:00 【海天鹰】

鹤观最东边隐藏的机关用羽毛照一下，出现5个石机关。

太难了，写个代码遍历一下。

采取随机击打的方式

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=yes"/>
<title>原神方石机关解密</title>
<style>
button { margin:10px; }
</style>
</head>
<body>
<p id='p'> https: //www.bilibili.com/read/cv12370247</p>
<p id='order'></p>
<p id='count'></p>
<div id='result'></div>
<script>
var a = 1, b = 2, c = 2, d = 1, e = 3;
var ac = 0, bc = 0, cc = 0, dc = 0, ec = 0;
var order='';
document.getElementById('p').innerText = '初始 (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';

function hit() {
    var r = Math.floor(Math.random() * 5) + 1;
    if (r == 1) {
        order += 'a';
        ac++;
        if (a < 3)
            a++;
        else
            a = 1;
        /*
        if (e < 3)
            e++;
        else
            e = 1;
        */
        if (b < 3)
            b++;
        else
            b = 1;
        var button = document.createElement('button');
        button.innerText = 'a:' + ac + ' (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';
        document.getElementById('result').appendChild(button);
    }

    if (r == 2) {
        order += 'b';
        bc++;
        if (b < 3)
            b++;
        else
            b = 1;
        if (a < 3)
            a++;
        else
            a = 1;
        if (c < 3)
            c++;
        else
            c = 1;
        var button = document.createElement('button');
        button.innerText = 'b:' + bc + ' (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';
        document.getElementById('result').appendChild(button);
    }

    if (r == 3) {
        order += 'c';
        cc++;
        if (c < 3)
            c++;
        else
            c = 1;
        if (b < 3)
            b++;
        else
            b = 1;
        if (d < 3)
            d++;
        else
            d = 1;            
        var button = document.createElement('button');
        button.innerText = 'c:' + cc + ' (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';
        document.getElementById('result').appendChild(button);
    }

    if (r == 4) {
        order += 'd';
        dc++;
        if (d < 3)
            d++;
        else
            d = 1;
        if (c < 3)
            c++;
        else
            c = 1;
        if (e < 3)
            e++;
        else
            e = 1;
        var button = document.createElement('button');
        button.innerText = 'd:' + dc + ' (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';
        document.getElementById('result').appendChild(button);
    }

    if (r == 5) {
        order += 'e';
        ec++;
        if (e < 3)
            e++;
        else
            e = 1;
        if (d < 3)
            d++;
        else
            d = 1;
        /*
        if (a < 3)
            a++;
        else
            a = 1;
        */
        var button = document.createElement('button');
        button.innerText = 'e:' + ec + ' (' + a + ',' + b + ',' + c + ',' + d + ',' + e + ')';
        document.getElementById('result').appendChild(button);
    }
    
    document.getElementById('order').innerText = '击打顺序：' + order;
    document.getElementById('count').innerHTML = 'a:' + ac + ', b:' + bc + ', c:' + cc + ', d:' + dc + ', e:' + ec + '<br>总击打次数：' + (ac+bc+cc+dc+ec);    
    
    if (a == 3 && b == 3 && c == 3 && d == 3 && e == 3){
        clearInterval(id);        
    }        
}
var id = setInterval(hit, 10);
</script>
</body>
</html>

刷出的最少击打次数

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原网站

版权声明
本文为[海天鹰]所创，转载请带上原文链接，感谢
https://blog.csdn.net/sonichty/article/details/125407050

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