Date (day 76)

1： subject

 It's today  2012  year  4  month  12  Thursday, Sunday , Programming , Enter from today to  12  month  31  Any date between days , What day of the week is the output day .

 Input format 
 There are two lines , The first line contains an integer  m, Indicates the month of the inquiry date .

 The second line contains an integer  d, The date of inquiry is the day of the month .

 Output format 
 The date of the output query is the day of the week .

 Be careful , In English .

 The English expression of Monday to Sunday is as follows ：

"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"
 Data range 
4≤m≤12,
1≤d≤31,
 Guarantee that the date is legal .

 sample input ：
5
20
 sample output ：
Sunday

2： Code implementation

#include <iostream>
#include <cstring>
#include <algorithm>

using namespace std;

const int months[] = {
    
    0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
};

int main()
{
    
    int month, date;
    cin >> month >> date;

    int m = 4, d = 12, day = 4;
    while (m < month || d < date)
    {
    
        d ++ ;
        if (d > months[m])
        {
    
            d = 1;
            m ++ ;
        }
        day = (day + 1) % 7;
    }

    string names[] = {
    
        "Sunday", "Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"
    };

    cout << names[day] << endl;

    return 0;
}