Do static code blocks always execute first? The pattern is smaller!!!

public class Test
{
    public static Test t1 = new Test();
    {
         System.out.println("blockA");
    }
    static
    {
        System.out.println("blockB");
    }
    public static void main(String[] args)
    {
        Test t2 = new Test();
    }
 }

answer ：blockAblockBblockA

I have a little question before I do this problem , Why don't you load the contents of static code first , Cause me to do wrong ！

After reading the solution , Find out         publicstaticTest t1 = newTest();    This created object t1 It's also static , So here comes the conclusion ： When all are static , Execute in sequence ！ So after creating the static t1 after , Execute the creation step by step t1 Constructor code block triggered when , Then execute the static code block in sequence , Then, after executing the create t2 Construction code block of time ！

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But if I put static code blocks in   publicstaticTest t1 = newTest(); What will happen before this statement is executed ？

answer ：

blockBblockAblockA

Here is the reference to the red sentence just said ！！！