Gson and fastjson

background

The company pays more attention to safety , And then recently fastjson Vulnerabilities appear a little more frequently , So ask for , Try not to use fastjson, So the team leader chose gson As a substitute .

Use

About json, I'm in the code , There are two places most commonly used , One is used for type conversion , The other is laziness , When calling the third-party interface, it is used to receive data . Let's take a look at gson and fastjson Use

gson

        /** * List《==》json */
        List<String> stringList = Lists.newArrayList("a", "b", "c", "d");
        String listJsonString = gson.toJson(stringList);
        System.out.println(stringList);
        System.out.println(listJsonString);
        List<String> jsonString = gson.fromJson(listJsonString, new TypeToken<List<String>>(){
    }.getType());
        System.out.println(jsonString);

        /** * map <==> json */
        Map<Integer, String> stringMap = new HashMap<>();
        stringMap.put(1, "one");
        stringMap.put(2, "two");
        String mapJson = gson.toJson(stringMap);
        Map<Integer, String> jsonD = gson.fromJson(mapJson, new TypeToken<Map<Integer, String>>(){
    }.getType());
        System.out.println(jsonD);
        System.out.println(jsonD.get(1));


        /** * List<object> <==> json */
        Customer customer = customerMapper.selectByPrimaryKey(1);

        List<Customer> customers = new ArrayList<>();
        customers.add(customer);
        customers.add(customer);
        String customerListString = gson.toJson(customers);
        System.out.println(customerListString);
        List<Customer> deS = gson.fromJson(customerListString, List.class);
        System.out.println(deS);

        /** * object <==> json */
        String customerJson = gson.toJson(customer);
        JsonObject jsonObject = gson.fromJson(customerJson, JsonObject.class);
        String crmId = jsonObject.get("crmId").getAsString();
        System.out.println("crmId:" + crmId);

        Customer customer1 = gson.fromJson(customerJson, Customer.class);
        System.out.println(customer1);

fastjson

        /** * List《==》fastjson */
        List<String> stringList = Lists.newArrayList("a", "b", "c", "d");
        String listJsonString = JSONObject.toJSONString(stringList);
        System.out.println(stringList);
        System.out.println(listJsonString);
        List<String> jsonString = JSONObject.parseArray(listJsonString, String.class);
        System.out.println(jsonString);

        /** * map <==> json */
        Map<Integer, String> stringMap = new HashMap<>();
        stringMap.put(1, "one");
        stringMap.put(2, "two");
        String mapJson = JSONObject.toJSONString(stringMap);
        Map<Integer, String> jsonD = (Map<Integer, String>) JSONObject.parse(mapJson);
        System.out.println(jsonD);
        System.out.println(jsonD.get(1));


        /** * List<object> <==> json */
        Customer customer = customerMapper.selectByPrimaryKey(1);

        List<Customer> customers = new ArrayList<>();
        customers.add(customer);
        customers.add(customer);
        String customerListString = JSONObject.toJSONString(customers);
        System.out.println(customerListString);
        List<Customer> deS = JSONObject.parseArray(customerListString, Customer.class);
        System.out.println(deS);


        /** * object <==> json */
        String customerJson = JSONObject.toJSONString(customer);
        JSONObject jsonObject = JSONObject.parseObject(customerJson);
        String crmId = jsonObject.getString("crmId");
        System.out.println("crmId:" + crmId);

        Customer customer1 = JSONObject.parseObject(customerJson, Customer.class);
        System.out.println(customer1);

choice

In terms of speed ,fastjson It's better than gson fast , At present, our service , It's not time to consider performance , So now from fastjson Switch to gson, Don't solve the performance problem for the time being .