MIPS assembly language learning-01-sum of two numbers, environment configuration and how to run

One 、 Personal understanding

Assembly language is a general term for a class of languages , Can be subdivided into ：X86,ARM,MIPS etc. , The portability of this kind of language is compared with C、Python、Java Poor , Because every type of Cpu The corresponding instruction sets are different , We all need to study alone .

Two 、MIPS Simulator download address

（1） Baidu cloud disk

 link ：https://pan.baidu.com/s/1qCmW0XERz2XxsbzEd2vxMw 
 Extraction code ：nddi

（2） Download from the official website

MARS-MIPS Official website

3、 ... and 、 How to use MARS

（1） install

install JDK, The version installed here is ：java version “1.8.0_331”,JDK The specific method of installation can be searched on the Internet , I won't go into more details here .

（2） function MARS

Double click .

（3） The actual effect

Four 、 Source code

mips-Sum.asm

li $t1 ,1
li $t2 ,2
add $t0 ,$t2 ,$t1
move $a0 ,$t0
li $v0 ,1
#$vo 1:Int 4:String
#print $a0
syscall

# No. is a comment

5、 ... and 、 Code interpretation

After installation, you should see a register list on the right

（1） matters needing attention

When storing numeric types , We need to use $t0 to $t7.
When you need to print data , We need to pay attention to the following ：
（1）$vo by 1 Print when Int Type data , by 4 When printing String Type data .
（2） The print function only prints $a0 Data in .

（2） Grammar explanation

li $t1 ,1
li $t2 ,2

li It's data 1,2 Put them into registers respectively $t1、$t2 in .

add $t0 ,$t2 ,$t1

add Is a register $t1、$t2 Add and store the data in $t0 in .

move $a0 ,$t0

move The way is to put $t0 Number of moves to $a0

li $v0 ,1

li It's data 1 Put it in the register $v0 in , For subsequent printing Int Type data .

syscall

syscall The method is to print $a0 Data in

6、 ... and 、 Run code

（1） Point to Execute

(2) spot Run->Assemble, Point again Run I/0

（3） Point by step

Now the first line is marked yellow , We click the step by step button .

Now the second line is marked yellow , We found on the right $t1 Turn into 16 It's binary 1, Let's continue to click the step by step button .

Now the third line is marked yellow , We found on the right $t2 Turn into 16 It's binary 2, Let's continue to click the step by step button .

Now the fourth line is marked yellow , We found on the right $t0 Turn into 16 It's binary 3, It is the $t2 and $t1 The value of is put in $t0 in , Let's continue to click the step by step button .

Now the fifth line is marked yellow , We found on the right $a0 Turn into 16 It's binary 3, Let's continue to click the step by step button .

Now the sixth line is marked yellow , We found on the right $v0 Turn into 16 It's binary 1, Let's continue to click the step by step button .

The console printed out 3.