Number of printouts (solved by recursive method)

#include <stdio.h>

void print_out(unsigned int n)
{
    
	if ( n >= 10)
	{
    
		printf("-%01d\r\n",n/10);
		print_out(n/10);
	}
	printf("%01d",n%10);

}
int main(int argc, char *argv[])
{
    
	printf("Hello C-Free!\n");
	print_out(12345);
	printf("\n");
	
	return 0;
}

The operation results are as follows ：