Zzuli:1072 frog climbing well

Title Description

There is a mouth with a depth of high Meter well , There is a frog at the bottom of the well , It can climb up the well wall every day up rice , At night, it slides down the shaft wall down rice , If frogs start crawling out one morning , For any specified high、up and down value （ All are natural numbers ）, Calculate how many days a frog can climb out of the wellhead ？

Input

Input 3 A positive integer ：high、up and down.

Output

Output an integer , Days . The output is on a single line .

The sample input  Copy

10 2 1

Sample output  Copy

9

Tips

Loop simulation . Be careful , We can't simply think that the rising height every day is equal to the climbing distance during the day minus the falling distance at night , Because if you can climb out of the wellhead during the day , You don't have to wait until night .

#include <stdio.h>
int main()
{
	int x=0,sum=0,day=1,high,up,down;
	scanf("%d%d%d",&high,&up,&down);
	while(1)
	{
		sum+=up;
		if(sum>=high)
		break;
		sum-=down;
		day++;
	}
	printf("%d",day);
	return 0;
}