SQLite reader plug-in tests SQLite syntax

A very useful plug-in , To do it SQLite Database creation , Data insertion modification , Delete , Update and other test verification .

1. Installing a plug-in

https://chrome.google.com/webstore/detail/sqlite-reader/clpnhenadbibdbfendahnlakkcpocmej

Easy browsing , Edit and manage... In the browser SQLite database ！

SQLite Reader Is an extension , It can help you browse easily , Edit and render SQLite Database . On our website , You can easily get from PC or Google Drive Load in SQLite Database , Edit the database and save the file in PC Go up or Google On the cloud hard disk , You don't have to save it to your desktop . You can use all the actions in the browser ！ The software 100％ Free of charge , You don't have to pay .

2. test SQLite

https://sqlreader.freebusinessapps.net/reader

You can load the database locally , You can also load the database from the network disk , You can plug-ins Sample database

```sql
DROP TABLE IF EXISTS colleagues;

CREATE TABLE colleagues(id integer,name text,title text,manager integer,hired date,salary integer,commission float, dept integer);

  INSERT INTO colleagues VALUES (1,'JOHNSON','ADMIN',6,'2011-12-17',18000,NULL,4);

  INSERT INTO colleagues VALUES (2,'HARDING','MANAGER',9,'2011-02-02',52000,300,3);

  INSERT INTO colleagues VALUES (3,'TAFT','SALES I',2,'2015-01-02',25000,500,3);

  INSERT INTO colleagues VALUES (4,'HOOVER','SALES II',2,'2011-04-02',27000,NULL,3);

  INSERT INTO colleagues VALUES (5,'LINCOLN','TECH',6,'2012-06-23',22500,1400,4);

  INSERT INTO colleagues VALUES (6,'GARFIELD','MANAGER',9,'2013-05-01',54000,NULL,4);

  INSERT INTO colleagues VALUES (7,'POLK','TECH',6,'2014-09-22',25000,NULL,4);

  INSERT INTO colleagues VALUES (8,'GRANT','ENGINEER',10,'2014-03-30',32000,NULL,2);

  INSERT INTO colleagues VALUES (9,'JACKSON','CEO',NULL,'2011-01-01',75000,NULL,4);

  INSERT INTO colleagues VALUES (10,'FILLMORE','MANAGER',9,'2012-08-09',56000,NULL,2);

  INSERT INTO colleagues VALUES (11,'ADAMS','ENGINEER',10,'2015-03-15',34000,NULL,2);

  INSERT INTO colleagues VALUES (12,'WASHINGTON','ADMIN',6,'2011-04-16',18000,NULL,4);

  INSERT INTO colleagues VALUES (13,'MONROE','ENGINEER',10,'2017-12-03',30000,NULL,2);

  INSERT INTO colleagues VALUES (14,'ROOSEVELT','CPA',9,'2016-10-12',35000,NULL,1);

SELECT name, hired FROM colleagues ORDER BY hired ASC;

SELECT title, COUNT(*) AS count, (AVG(salary)) AS salary FROM colleagues GROUP BY title ORDER BY salary DESC;

  

![](https://img-blog.csdnimg.cn/img_convert/f4ea1b02730049d0545d4352f355c420.png)

  

 The results are as follows ：

  

![](https://img-blog.csdnimg.cn/img_convert/d964a6bf8d51cb8e73697d3e476dec83.png)

  

** Basic grammar and common SQL Grammatical similarity .**

 Delete data table usage  drop:

DROP TABLE IF EXISTS  Table name ;

  

 Create table  CREATE：

CREATE TABLE  Table name ( Field name   type , Field name 2  type 2);

  

 insert data  Insert:

 INSERT INTO  Table name  VALUES ( value , value 2);

  

 Query data  Select:

SELECT  Field name  FROM  Table name  ORDER BY  Field name  ASC;

  

 Modifying data UPDATA：

UPDATE  Table name  SET  Field name =" value " where  Field name = value