my_ Implementation of strcpy (classic, simple, practical, collection)

C Defined in the language function library strcpy What does it look like ？

This is a cpulspuls The note above （ Click to enter the annotation page ）, If you are interested, you can go into the website carefully .
The standard explanation tells us ,strcpy The return type of is char*, That is, the character pointer type , Equivalent to the first address of the string array , The function strcpy（arr1,arr2） Is that take arr2 The content of copy To arr1 in , however arr2 The contents of the remain unchanged .
Here is cplusplus The above example ：

/* strcpy example */
#include <stdio.h>
#include <string.h>

int main ()
{
    
  char str1[]="Sample string";
  char str2[40];
  char str3[40];
  strcpy (str2,str1);
  strcpy (str3,"copy successful");
  printf ("str1: %s\nstr2: %s\nstr3: %s\n",str1,str2,str3);
  return 0;
}

Output ：

str1: Sample string
str2: Sample string
str3: copy successful

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How to write your own quickly, accurately and ruthlessly my_strcpy?

Here's my approach , With notes , I hope you can correct me ！

#include<stdio.h>
char* my_strcpy(char* destination,const char* resource)// This const But very important , But very important , because arr2 It's something we don't want to change 
{
    
	char* ret = destination;// Remember the address of the target , Later as return The object of 
	while(*destination++=*resource++)// Here *resource The content of is not \0 When , Its content is assigned to 
	{
                                    //arr1 That is, the target string , Finally, when \0 When the assignment is finished ,while() loop 
		;                            // The judgment condition is false , Termination operation , At this time, our goal has been achieved .
	}
	return ret;// Return the first address of the modified string , It is equivalent to returning the modified target string 
}
int main()
{
    
	char arr1[] = {
    "xxxxxxxxxxxx"};
	char arr2[] = {
    "jinitaimei"};
  	my_strcpy(arr1,arr2);// Call function 
	printf("%s\n",arr1);
	return 0;
}

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