Store the numbers in the array in reverse order

This question requires the preparation of procedures , Will be given n An integer is stored in the array , Put this... In the array n The number is stored in reverse order , Then output the elements in the array in order .

Input format :

Input gives a positive integer in the first line n（1≤n≤10）. Second line input n It's an integer , Separate with spaces .

Output format :

Output this on one line n The processing result of an integer , Adjacent numbers are separated by a space , There must be no extra space at the end of the line .

sample input :

4
10 8 1 2

sample output :

2 1 8 10

Code ： 

#include <stdio.h>
int main(){
    int  a[10],N,i,temp,n;
    scanf("%d",&N);
    for(i=0;i<N;i++){
        scanf("%d",&a[i]);
    }
    if(N%2==0){
        n=N/2;
        for(i=0;i<n;i++){
        temp=a[i];
        a[i]=a[2*n-i-1];
        a[2*n-i-1]=temp;
    }
    }
    else {
        n=(N-1)/2;
        for(i=0;i<n;i++){
        temp=a[i];
        a[i]=a[2*n-i];
        a[2*n-i]=temp;
    }
    }
    for(i=0;i<N-1;i++)printf("%d ",a[i]);
    printf("%d",a[i]);
    }