Find the minimum value and location in multiple numbers (with repetition)

Find the minimum value among the given numbers , And get the position of the minimum value in the number .

1. When there are no duplicate values in multiple numbers , Just walk through the list that stores these numbers ;
2. When there are duplicate values in multiple numbers , You can add a new list MinIndex To store the location of the current minimum , When the minimum value changes during traversal , It needs to be removed MinIndex And add the position of the new minimum value to MinIndex in , When there is a duplicate value of the minimum value in the traversal process , You need to fill in the position of this value MinIndex in .

public static List<int> FindMin(List<float> NumList)
{
    
    List<int> MinIndex = new List<int>() {
     0 };
    float MinNum = NumList[0];

    for (int i = 1; i < NumList.Count; i++)
    {
    
        // If the minimum value changes , Then change the minimum value ,
        // And clear the List, And add the position of the current value 
        if (MinNum > NumList[i])
        {
    
            MinNum = NumList[i];
            MinIndex.Clear();
            MinIndex.Add(i);
        }
        // If duplicate values occur , The position of the current value is also added to the position of the record minimum List
        else if (MinNum == NumList[i])
        {
    
            MinIndex.Add(i);
        }
    }
    
    // When the minimum value repeats , Record the position of the minimum value List There will be multiple numbers 
    // If only one minimum position is required , Yes, you can. List Sort at random , Then go to List[0] that will do 
    if (MinIndex.Count > 1)
    {
    
        System.Random rand = new System.Random();
        List<int> RandList = new List<int>();
        foreach (int i in MinIndex)
        {
    
            RandList.Insert(rand.Next(RandList.Count), i);
        }

        return RandList;
    }
    else
    {
    
        return MinIndex;
    }
}